Assumption: (0.9999~) + (0.000~1) = 1
Nate’s statement: (0.9999~) = 1
Concusion: 1 + 0.000~1 = 1
Further conclusion: 1 + (0.000~1 + 0.000~1 + 0.000~1 + …) = 1
So you can add infinite sets of 0.000~1 to 1 and the sum will always be 1? Not 1.000~1, 1.000~2, 1.000~3, etc.?